Answer:
Justin is 1 feet far away from Brandon
Step-by-step explanation:
As shown in the diagram, we let the distance between Justin and Brandon be x
[tex]Speed = \frac{distance}{time} [/tex]
from the question
the total time taken by the ball to reach Brandson=4s
Also the total distance is travelled by the ball=19+x
while the average speed=5ft/s
By substitution we obtain
[tex]5 = \frac{19 + x}{4} [/tex]
[tex] \implies4 \times 5 = 19 + x[/tex]
[tex]\implies20=19 + x[/tex]
[tex]\implies20 - 19 = x[/tex]
x=1 feet
