Answer:
The answer is: [tex]\frac{1}{8}[/tex]
Step-by-step explanation:
The sample space when tossing a coin three times is [HHH, HHT, HTH, HTT, THH, THT, TTH, TTT] and the total number of occurrence is 8.
Getting Head on first toss, tail on second and third is: HTT and it occurs just once in our sample space.
Therefore, the probability of getting Head on first toss, tails on second and third tosses is: [tex]\frac{1}{8}[/tex]
Note probability = [tex]\frac{number of possible occurrence}{number of total occurrence}[/tex]
