Wire resistor A has twice the length and twice the cross sectional area of wire resistor B. Which of the following accurately compares the resistances of wire resistors A and B?a) Wire A has twice the resistance of wire B.b) Wire A has half the resistance of wire B.c) Wire A has the same resistance as wire B.d) None of the above

Respuesta :

Answer: Option (c) is the correct answer.

Explanation:

It is known that the relation between resistance, length and cross-sectional area is as follows.

          R = [tex]\rho \frac{l}{A}[/tex]

Let the resistance of resistor A is denoted by R and the resistance of resistor B is denoted by R'.

Hence, for resistor A the expression for resistance according to the given data is as follows.

                 R = [tex]\rho \frac{2l}{2A}[/tex]

On cancelling the common terms we get the expression as follows.

             R = [tex]\rho \frac{l}{A}[/tex]

Now, the resistance for resistor B is as follows.

           R' = [tex]\rho \frac{l'}{A'}[/tex]

Thus, we can conclude that the statement, Wire A has the same resistance as wire B, accurately compares the resistances of wire resistors A and B.