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An ideal heat engine operates of fixed difference of temperatures between hot and cold reservoirs, say 100K. What will provide greater efficiency: operation with the hot reservoir as hot as possible, or operation with a cold reservoir as cold as possible?

Respuesta :

cjmejiab

To solve this problem we will apply the concepts given for the efficiency of an engine which is given as

[tex]\eta = 1-\frac{T_C}{T_H}[/tex]

[tex]\eta = \frac{T_H-T_C}{T_H}[/tex]

Where

[tex]T_C[/tex] = Temperature of the cold reservoir

[tex]T_H[/tex] = Temperature of the hot reservoir

The efficiency maximum would be given only if [tex]T_C = 0[/tex]

Replacing this value we have

[tex]\eta = \frac{T_H-0}{T_H}[/tex]

[tex]\eta = 1[/tex]

Therefore: Cold reservoir as cold as possible provide the greater efficiency.

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