Answer
After inland population after migration allele frequency is 0.62 or 62%
Explanation:
Given,
Coastal striped phenotype freq. = 0.22
ss = 0.22
[tex]q_{coastal} \times q_{coastal} = 0.22[/tex]
[tex]q_{2 coastal}[/tex]= 0.22
Similarly, inland striped phenotype freq. = 0.43
[tex]q_{2inland}[/tex] = 0.43
[tex]q_{coastal} = \sqrt{q_{2coastal}}[/tex]
= [tex]\sqrt{0.22}[/tex]
= 0.4690
[tex]q_{coastal}[/tex]= 0.47 i.e. 47%
[tex]q_{inland} = \sqrt{0.43}[/tex]
= 0.655
[tex]q_{inland}[/tex] = 0.66 i.e. 66%
the migration range (m) is given as 20%
m= 0.2
allele freq. after migration = pre migration + ∆q
here,
∆q = change in the allele frequency
or
migration of allele freq. from coastal to inland
=[tex]m(q_{coastal} - q_{inland})[/tex]
= 0.2 (0.47 – 0.66)
=[tex]0.2 \times (- 0.191)[/tex]
= - 0.0382
∆q = -0.04 i.e. 4%
