Answer:
The peak value of current will be 2.828 A.
Explanation:
Given that
Value of RMS current I(rms) = 2 A
Lets take peak current = I(p)
As we know that relationship between RMS and peak current given as
[tex]I(rms)=\dfrac{I(p)}{\sqrt2}[/tex]
Now by putting the values in the above equation
[tex]I(rms)=\dfrac{I(p)}{\sqrt2}[/tex]
[tex]2\ A=\dfrac{I(p)}{\sqrt2}[/tex]
[tex]I(p)=2\sqrt2[/tex]
As we know that
[tex]\sqrt{2}=1.414[/tex]
Therefore
I(p)=2.828 A
The peak value of current will be 2.828 A.
