The reflector of a flashlight is in the shape of a parabolic surface. The casting has a diameter of 8 inches and a depth of 4 inches.
How far should The light bulb should be placed from the vertex?

Respuesta :

Answer:

1 in

Step-by-step explanation:

We are given that

Diameter of casting=8 in

Radius of casting=[tex]\frac{Diameter}{2}=4 in[/tex]

Depth of casting=4 in

We have to find the distance of light bulb should be from the vertex

It means the reflector passing through the point (4,4).

Equation of parabola along y-axis is given by

[tex]x^2=4ay[/tex]

Using the equation substitute x=4 and y=4

[tex]16=16a[/tex]

[tex]a=\frac{16}{16}=1[/tex]

The focus of parabola is at (0,a).

Therefore, the focus of reflector=(0,1)

Hence, the light bulb should be placed 1 in far  from the vertex.

The distance of light bulb can be calculated using equation of parabola. The parabola is a plane curve which is U-shaped.

The distance of light bulb is [tex]1\:\rm in[/tex].

Given:

The diameter is [tex]8\:\rm in[/tex].

The radius is [tex]=\frac{d}{2}=\frac{8}{2}=4 \:\rm in[/tex].

The depth is [tex]4\:\rm in[/tex].

Since the depth is [tex]4\:\rm in[/tex] and radius is [tex]4\:\rm in[/tex] so reflector passes through the point [tex](4,4)[/tex].

Write the equation of parabola for y-axis.

[tex]x^2=4ay[/tex]

Putting [tex]4[/tex] for [tex]x[/tex] and [tex]4[/tex] for [tex]y[/tex].

[tex]4^2=4\times a\times 4\\a=\frac{16}{16}\\a=1[/tex]

The focus of a parabola is [tex](0,1)[/tex].

The distance of light bulb is [tex]1\:\rm in[/tex].

Learn more about parabola here:

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