The base composition of an RNA virus was analyzed and found to be 14.1% A, 14.0% U, 36.2% G, and 35.7% C. Would you conclude that the viral genetic material is single-stranded RNA or double-stranded RNA? 2. The genetic material found within some viruses is single-stranded DNA. Would this genetic material contain equal amounts of A and T and equal amounts of G and C?

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Answer:

The correct answer will be -

1. Genetic material of virus is- dsRNA

2. ssDNA does not have equal amount

Explanation:

According to Chargaff's rule the amount of Adenine=Thymine/Uracil and Guanine=Cytosine in the double-stranded DNA or RNA.

If the content of A and U are equal that is 14.1% and G and C are almost equal therefore it follows the Chargaff rule and thus the genetic material is the ds RNA molecule.

The Chargaff rule is not applicable where the genetic material is single-stranded so if the material is single-stranded therefore the A is not equal to T and G is not equal to C.

Thus, dsRNA and ssDNA does not have equal amount is the correct answer.

The genetic material of the organism can be DNA or RNA. The genetic material of the virus is dsRNA and the ssDNA will not have an equal amount of the bases.

What is the Base pairing rule?

The genetic material of the organisms follows the base-pairing rule of the Chargaff and is applicable to the double-stranded DNA.

According to the rule, the amount of the adenine is equivalent to the thymine or uracil and cytosine to the guanine. The molecule follows Chargaff's rule of base pairing and hence can be a double-stranded RNA molecule.

In the case of the single-stranded DNA, the amount of the adenine, guanine, cytosine, and thymine does not follow the Chargaff's base and hence will not have an equal amount of the bases.

Therefore, the virus will have ds RNA and the ssDNA will not have the same composition of the bases.

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