Respuesta :
Answer:
In summation form [tex]\sum_{n = 1} ^{5} 6(6)^{n - 1}[/tex]
Step-by-step explanation:
Within one hour, the first person gives a stack of flyers to six people and within the next hour, those six people give a stack of flyers to six new people.
So, in the first 5 hours, the summation of people that receive a stack of flyers not including the initial person will be given by
6 + (6 × 6) + (6 × 6 × 6) + (6 × 6 × 6 × 6) + (6 × 6 × 6 × 6 × 6).
So, in summation form [tex]\sum_{n = 1} ^{5} 6(6)^{n - 1}[/tex]
Therefore, Sigma-Summation Underscript n = 1 Overscript 5 EndScripts 6 (6) Superscript n minus 1, gives the correct solution. (Answer)
We can evaluate how many persons are getting flyer by each person then calculate summation.
Option A: [tex]\sum^5_{n=1}6(6)^{(n-1)}\\[/tex]summation form.
How to find the total number of persons getting the flyers?
First person gives flyers to 6 people.
Those 6 persons give flyers to 6 new people, thus [tex]6 \times 6 = 36[/tex] people...
And so on five times for five hour as this process is done on hourly basis.
Thus, the summation without including first person, for five hours to count total number of people who received flyers is:
[tex]6 + (6 \times 6) + (6 \times 6 \times 6) + (6 \times 6 \times 6 \times 6 ) + (6 \times 6 \times 6 \times 6 \times 6)[/tex]
or in summation it can be rewritten as:
[tex]\sum^5_{n=1}6(6)^{(n-1)}\\[/tex]
Thus, Option A: [tex]\sum^5_{n=1}6(6)^{(n-1)}\\[/tex] is the needed summation form.
Learn more about summation here:
https://brainly.com/question/14626490
