The required equation of the line is [tex]\rm y = \dfrac{5}{6}x-2[/tex].
Given that,
The equation of the line is,
[tex]\rm y = \dfrac{5}{6}(x-10)[/tex]
It passes through the point (12, 8).
We have to determine
The equation of the line is parallel to the given line.
According to the question,
The equation of the line is,
[tex]\rm y = \dfrac{5}{6}(x-10)[/tex]
The slope of the line [tex]\rm m_1[/tex] is 5/6.
If the two lines are parallel to each other then the slope of these lines is the same.
[tex]\rm m_1 = m_2\\\\\dfrac{5}{6} = \dfrac{5}{6}[/tex]
Therefore,
The equation of line passes through the point (12, 8) is,
[tex]\rm( y -y_1) = m (x-x_1)\\\\(y-8) = \dfrac{5}{6} (x-12)\\\\6 (y-8) = 5(x-12)\\\\6y-48=5x-60\\\\6y = 5x-60+48\\\\6y = 5x-12\\\\y = \dfrac{5}{6}x- \dfrac{12}{6}\\\\y = \dfrac{5}{6}x-2[/tex]
Hence, The required equation of the line is [tex]\rm y = \dfrac{5}{6}x-2[/tex].
For more details refer to the link given below.
https://brainly.com/question/9351049?
