Answer:
111.657596
Explanation:
The expression of volume is given by
[tex]V=1001.93+111.5282+0.64698m^2[/tex]
Partially differentiating the term we get
[tex]\dfrac{\partial V}{\partial x}=\dfrac{\partial (1001.93+111.5282+0.64698m^2)}{\partial x}\\\Rightarrow \dfrac{\partial V}{\partial x}=111.5282+2\times 0.64698m\\\Rightarrow \dfrac{\partial V}{\partial x}=111.5282+1.29396m[/tex]
m = 0.100
[tex]\dfrac{\partial V}{\partial x}=111.5282+1.29396\times 0.100\\\Rightarrow \dfrac{\partial V}{\partial x}=111.657596[/tex]
The partial molar volume of glucose is 111.657596
