Answer : The Lewis-dot structure of the following molecules are shown below.
Explanation :
Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.
In the Lewis-dot structure the valance electrons are shown by 'dot'.
(1) The given molecule is, [tex]NH_3[/tex]
As we know that hydrogen has '1' valence electron, nitrogen has '5' valence electrons.
Therefore, the total number of valence electrons in [tex]NH_3[/tex] = 5 + 3(1) = 8
According to Lewis-dot structure, there are 6 number of bonding electrons and 2 number of non-bonding electrons.
(2) The given molecule is, [tex]SO_2[/tex]
As we know that sulfur and oxygen has '6' valence electrons.
Therefore, the total number of valence electrons in [tex]SO_2[/tex] = 6 + 2(6) = 18
According to Lewis-dot structure, there are 8 number of bonding electrons and 10 number of non-bonding electrons.
(3) The given molecule is, [tex]CH_3OH[/tex]
As we know that carbon has '4' valence electrons, hydrogen has '1' valence electron and oxygen has '6' valence electrons.
Therefore, the total number of valence electrons in [tex]CH_3OH[/tex] = 4 + 4(1) + 6 = 14
According to Lewis-dot structure, there are 10 number of bonding electrons and 4 number of non-bonding electrons.
(4) The given molecule is, [tex]HNO_2[/tex]
As we know that hydrogen has '1' valence electron, nitrogen has '5' valence electrons and oxygen has '6' valence electrons.
Therefore, the total number of valence electrons in [tex]HNO_2[/tex] = 1 + 5 + 2(6) = 18
According to Lewis-dot structure, there are 8 number of bonding electrons and 10 number of non-bonding electrons.
(5) The given molecule is, [tex]N_2[/tex]
As we know that nitrogen has '5' valence electrons.
Therefore, the total number of valence electrons in [tex]N_2[/tex] = 2(5) = 10
According to Lewis-dot structure, there are 6 number of bonding electrons and 4 number of non-bonding electrons.
(6) The given molecule is, [tex]CH_2O[/tex]
As we know that carbon has '4' valence electrons, hydrogen has '1' valence electron and oxygen has '6' valence electrons.
Therefore, the total number of valence electrons in [tex]CH_2O[/tex] = 4 + 2(1) + 6 = 12
According to Lewis-dot structure, there are 8 number of bonding electrons and 4 number of non-bonding electrons.
