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Tarzan steps out of his house and grabs a hanging vine to swing to the ground. If his house is 11.3 m above the ground, what is Tarzan's speed when he reaches the ground?

Respuesta :

Answer:

      v = 14.88 m / s

Explanation:

For this exercise let's use energy conservation. We place the reference system on the ground

Start. Tarzan before jumping

         Em₀ = U = m g h

Final. Upon reaching the ground

        [tex]Em_{f}[/tex]= K = ½ m v²

Energy is conserved

       Em₀ = [tex]Em_{f}[/tex]

        m g h = ½ m v²

        v² = 2gh

        v = √ 2gh

Let's calculate

        v = √ (2 9.8 11.3)

        v = 14.88 m / s

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