Answer:
x = 1.5[tex]t^{2}[/tex] , y = 3 + 2at.
Step-by-step explanation:
For the parabola [tex]Y^{2}[/tex] = 4aX ,
General form will be
(X = a[tex]t^{2}[/tex] , Y = 2at) ,
Thus , for the parabola [tex](y-3)^{2}[/tex] = 6(x +8)
Here , a = 1.5 and Y from the above equation should be substituted by y - 3 and X must be substituted by x + 8. After substitution of the same we can use the general equation formula for this parabola also.
Thus , general equation comes out to be :-
x + 8 = 1.5[tex]t^{2}[/tex] , y - 3 = 2at
x = 1.5[tex]t^{2}[/tex] , y = 3 + 2at.
