Answer:
Price of hamburgers = $2
Price of white-dogs = $3
Step-by-step explanation:
Let
The number price of hamburgers be x
The number price of white-dogs be y
Then the first family buys 3 hamburgers and 2 white -dogs for $13
3x + 2y = 13-----------------------------(1)
Another first family buys 2 hamburgers and 5 white -dogs for $16
2x + 5y = 16----------------------------(2)
To solve let us multiply eq(1) by 2 and eq(2) by 3, we get
6x + 4y = 26-----------------------------(3)
6x + 15y = 48----------------------------(4)
subracting (3) from (4)
6x + 15y = 48
6x + 4y = 26
(-)
-------------------------
11y = 22
---------------------------
[tex]y =\frac{22}{11}[/tex]
y =2
Now substituting the value of y in eq(1),
3x + 2(2) = 13
3x + 4 = 13
3x = 13-4
3x = 9
x =[tex]\frac{9}{3}[/tex]
x =3
