Answer:
The least value of (r+s) is (12+14)=26
Step-by-step explanation:
Well, first let us solve equation of 11(s-1)=13(r-1), which results in 11s-11=13r-13. Hence, 11s+2=13r. It is stated that r and s both are integers and greater than 1.
To make sure that r and s are integers, the least value of s must be equal to 14 (s=14) then the least value of r becomes 12 (r=12).
Finally, the least value of (r+s) is (12+14)=26.
