Answer:
Step-by-step explanation:
Plug this into the quadratic formula. It's the easiest and surest way to solve a quadratic.
a = 2
b = 1
c = 2
Filling in the quadratic formula:
[tex]x=\frac{-1+/-\sqrt{1^2-4(2)(2)} }{2*2}[/tex]
which simplifies to
[tex]x=\frac{-1+/-\sqrt{-15} }{4}[/tex]
You can't have a negative under the square root sign (or ay even index radical, for that matter), so we will rewrite it as
[tex]x=\frac{-1+/-\sqrt{(-1)(15)} }{4}[/tex]
and since i-squared is equal to -1:
[tex]x=\frac{-1+/-\sqrt{15i^2} }{4}[/tex]
The only perfect square we can pull out of that square root is the i from the i-squared, so when we do that we get:
[tex]x=-\frac{1+/-\sqrt{15}i }{4}[/tex]
or you could put the i out front; it doesn't change the answer at all. The third choice down is the one you want.
