Answer:
Option b) 36 over 25 is correct
That is given expression is equivalent to [tex]\frac{36}{25}[/tex]
Step-by-step explanation:
Given expression can be written as below:
[tex](\frac{7\times 3\times 2}{7\times 5})^2\times \frac{7^0}{5^{-3}}\times 5^{-9}[/tex]
To find the value of given expression:
[tex](\frac{7\times 3\times 2}{7\times 5})^2\times \frac{7^0}{5^{-3}}\times 5^{-9}=(\frac{6}{5})^2\times (\frac{1}{5^{-3}})^3\times \frac{1}{5^9}[/tex]
[tex]=(\frac{6}{5})^2\times (5^3)^3\times \frac{1}{5^9}[/tex]
[tex]=\frac{36}{25}\times 5^9\times \frac{1}{5^9}[/tex]
[tex]=\frac{36}{25}[/tex]
Therefore [tex](\frac{7\times 3\times 2}{7\times 5})^2\times \frac{7^0}{5^{-3}}\times 5^{-9}=\frac{36}{25}[/tex]
Option b) 36 over 25 is correct
That is given expression is equivalent to [tex]\frac{36}{25}[/tex]
