Note: As you missed to identify what we have to find in this question. But, after a little research, I am able to find that we had to find the Mode for the data given in your question. So, I am assuming we have to calculate the the Mode. Hopefully, it would clear your concept regarding this topic.
Answer:
The mode of the data = 75
Step-by-step explanation:
Lets visualize the given data in a table to show the frequency distribution:
Daily expenditure on milk (in Rs) Number of households
0-30 5
30-60 6
60-90 9
90-120 6
120-150 4
Here the maximum frequency is 9.
So, modal class is 60-90.
As the formula to calculate the mode:
[tex]Mode = l_{1} + h (\frac{f_{1}-f_{0}}{2f_{1}-f_{0}-f_{2}} )[/tex]
Here, the maximum
[tex]l_{1} =60, f_{1} =9, f_{0}=6, f_{0}=6, h=30[/tex]
[tex]l=[/tex] is the lower limit of the class
[tex]f_{1} =[/tex] is the frequency of the modal class
[tex]f_{0} =[/tex] is the frequency of the previous modal class
[tex]f_{2} =[/tex] is the frequency of the next previous modal class
[tex]l=[/tex] is the class size
So,
[tex]Mode = l_{1} + h (\frac{f_{1}-f_{0}}{2f_{1}-f_{0}-f_{2}} )[/tex]
[tex]Mode = 60 + 30 (\frac{9-6}{2(9)-6-6} )[/tex]
[tex]Mode = 60 + \frac{(30)(3)}{6}[/tex]
[tex]Mode = 60 + 15=75[/tex]
∴ The mode of the data = 75
Keywords: mode, frequency distribution
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