Answer:
The equation of a line that passes through the point (4, 2) and is perpendicular to the line whose equation is y=x3−1 is [tex]y = -\frac{1}{3}x +3.3[/tex]
Step-by-step explanation:
Given:
point (4,2)
perpendicular line y =3x -1
To find:
equation of the line =?
Solution:
We are given with perpendicular line . the slope of the perpendicular line will be negative, so let us take the reciprocal of the line and change its sign. bu doing so we will get,
slope = [tex]-\frac{1}{3}[/tex]
Now we know that the equation of the line is
y =mx+b----------------------(1)
where
m is the slope
b is the y intrcept
x,y are the points through which the line pass
so now substituting the values we get
[tex]2 =-\frac{1}{3} \times 4 +b[/tex]
[tex]2 = -1.3 +b[/tex]
b = 2 +1.3
b = 3.3
substituting in (1)
[tex]y = -\frac{1}{3}x +3.3[/tex]
