Answer:
[tex]\large\boxed{y+1=3(x-1)}\\\\\boxed{y=3x-4}[/tex]
Step-by-step explanation:
The point-slope form of an equation of a line:
[tex]y-y_1=m(x-x_1)[/tex]
m - slope
(x₁, y₁) - a point on a line
We have
[tex]m=3,\ (1,\ -1)\to x_1=1,\ y_1=-1[/tex]
Substitute:
[tex]y-(-1)=3(x-1)\\\\\boxed{y+1=3(x-1)}[/tex]
Convert to the slope-intercept form
[tex]y=mx+b[/tex]
m - slope
b - y-intercept
[tex]y+1=3(x-1)[/tex] use the distributive property
[tex]y+1=3x-3[/tex] subtract 1 from both sides
[tex]\boxed{y=3x-4}[/tex]
