Answer:
[tex]52884\,N[/tex]
Step-by-step explanation:
Let 'm' denotes the mass of helicopter, 'g' denotes the gravity and 'a' denotes the acceleration.
We know that [tex]F_{grav}=mg[/tex]
Put [tex]m=4520 kg\,,\,g=9.8 \,\,m/sec^2[/tex]
So,
[tex]F_{grav}=mg=4520(9.8)=44296\,N[/tex]
Also, as per Newton's second law,
[tex]F_{motion}=ma[/tex]
Put [tex]m=4520 kg\,,\,a=1.9 \,\,m/sec^2[/tex]
So,
[tex]F_{motion}=ma=4520(1.9)=8588\,N[/tex]
We know that the lift force is the sum of the gravitational force and the force of motion.
[tex]F_{lift}=F_{grav}+F_{motion}\\=44296\,N+8588\,N\\=52884\,N[/tex]
