Respuesta :
Answer:
a)[tex] \bar X = \frac{9+9+25+56+56+88+91+102+114+122+150+165}{12}=82.25 \approx 82[/tex]
[tex] Median = \frac{88+91}{2}=89.5\approx 90[/tex]
And the mode on this case would be 9 and 56 since both values are repeated two times, so we will have a bimodal distribution on this case.
b) For this case the measure of central tendecy important would be the mode . Because captures the central tendency accurately.
Step-by-step explanation:
For this case we have the following data:
102 56 25 9 9 56 165 88 122 150 91 114
We can begin the procedure ordering the data on increasing way and we got:
9 9 25 56 56 88 91 102 114 122 150 165
Part a
The mean can be calculated with the following formula:
[tex] \bar X = \frac{\sum_{i=1}^n X_i}{n}[/tex]
And if we replace we got:
[tex] \bar X = \frac{9+9+25+56+56+88+91+102+114+122+150+165}{12}=82.25 \approx 82[/tex]
Since we have 12 observations we can calculate the median as the average between the position 6 and 7 in the dataset ordered and we got:
[tex] Median = \frac{88+91}{2}=89.5\approx 90[/tex]
And the mode on this case would be 9 and 56 since both values are repeated two times, so we will have a bimodal distribution on this case.
Part b
For this case the measure of central tendecy important would be the mode. Because captures the central tendency accurately.
