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A technical machinist is asked to build a cubical steel tank that will hold 60L of water.Calculate in meters the smallest possible inside length of the tank. Round your answer to the nearest

Respuesta :

Answer:

Explanation:

Given

Total volume of tank [tex]V=60\ L\approx 60\times 10^{-3}\ m^3[/tex]

Suppose a is the side of cubical tank

volume of cubical tank [tex]a^3[/tex]

[tex]a^3=60\times 10^{-3}[/tex]

[tex]a=3.909\times 10^{-1}\ m[/tex]

[tex]a=0.39\ m[/tex]

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