Answer:
The inverse of the given relation is [tex]x=\sqrt{\frac{y+3}{7}}[/tex] .
Step-by-step explanation:
Given:
y=7x² - 3
Now, to find the inverse of the given relation.
[tex]y=7x^2-3[/tex]
So, adding both the sides by 3 we get:
[tex]y+3=7x^2[/tex]
Now, dividing both the sides by 7 we get:
[tex]\frac{y+3}{7} =x^2[/tex]
And, using square root on both the sides we get:
[tex]\sqrt{\frac{y+3}{7}} =x[/tex]
Thus:
[tex]x=\sqrt{\frac{y+3}{7}}[/tex]
Therefore, the inverse of the given relation is [tex]x=\sqrt{\frac{y+3}{7}}[/tex] .
