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You come across an open container that is filled with two liquids. Since the two liquids have different densities, there is a distinct separation between them. Water, which has a density of rhow=1.00×103 kg/m3 , fills the lower portion of the container to a depth of 0.218 m. The fluid that is floating on top of the water is 0.328 m deep. If the absolute pressure on the bottom of the container is 1.049×105 Pa , what is the density, rhol, of the unknown fluid? The acceleration due to gravity is g=9.81 m/s2 and atmospheric pressure is P0=1.013×105 Pa .

Respuesta :

Answer:

455.33 kg/m³

Explanation:    

The pressure at the bottom of the container is

P = P' + P'' +P₀

P' is pressure due to water

P'' is pressure due to unknown liquid

P₀ is the atmospheric pressure

P = 1.049 ×10⁵ Pa

P' = ρgh

⇒P' = (1000)(9.8)(0.218) =2136.4 Pa

P'' =P-P'-P₀

⇒P''=( 1.049 ×10⁵-2136.4-1.013 ×10⁵) Pa =1463.6 Pa

P'' = ρ'gh'

ρ' = (1463.6)/(9.8×0.328) = 455.33 kg/m³

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