Answer:
Golf ball
Explanation:
Time of flight when the gold ball is thrown horizontally:
h = 0 + 0.5 gt'²
[tex] t'= \sqrt{\frac{2h}{g}[/tex]
When the bowling ball is thrown vertically upwards, the net vertical displacement = h. vertical velocity = u
[tex]h= - ut + 0.5 gt^2 \\ \Rightarrow 0.5gt^2-ut-h = 0\\ \Rightarrow gt^2-2ut-2h =0[/tex]
[tex]t = \frac{2u \pm \sqrt{(-2u)^2-4(g)(-2h)}}{2g}\\ t=\frac{2u \pm \sqrt{4u^2+8gh}}{2g}[/tex]
[tex]t=\frac{u\pm\sqrt{u^2+2gh}}{g}[/tex]
t'<t
The golf ball will hit the ground first.
