The force exerted on the side of the house is [tex]\rm 2.09598 \times 10^6 \ N[/tex] due to the given explosion.
From the formula of pressure,
[tex]P = \dfrac FA[/tex]
Where,
[tex]P[/tex] - pressure = 0.2 atm × 1.013×10⁵ Pa = [tex]2.052\times 10^9 \rm \ Pa[/tex]
[tex]F[/tex] - Force = ?
[tex]A[/tex] - area = 3.89 m × 22.6 m = [tex]\bold {87.914\rm \ m^2}[/tex]
So,
[tex]F = P\times A[/tex]
Put the values in the formula,
[tex]F = 2.052\times 10^9 \rm \ Pa \times 87.914 \ m^2\\\\\it {F}=\rm 2.09598 \times 10^6 \ N[/tex]
Therefore, the force exerted on the side of the house is [tex]\rm 2.09598 \times 10^6 \ N[/tex] due to the given explosion.
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