Respuesta :
The cost of each senior ticket is $ 5 and cost of each child ticket is $ 12
Solution:
Let "a" be the price of each senior ticket
Let "b" be the price of each child ticket
On the first day of ticket sales the school sold 4 senior tickets and 4 child tickets for a to total of 68
Thus a equation is framed as:
4 senior tickets x price of each senior ticket + 4 child tickets x price of each child ticket = 68
[tex]4 \times a + 4 \times b = 68[/tex]
4a + 4b = 68 ---------- eqn 1
The school took in 120 on the second day by selling 12 senior tickets and 5 child tickets
Similarly, we frame a equation as:
[tex]12 \times a + 5 \times b = 120[/tex]
12a + 5b = 120 ---------- eqn 2
Let us solve eqn 1 and eqn 2
Multiply eqn 1 by 3
12a + 12b = 204 -------- eqn 3
Subtract eqn 2 from eqn 3
12a + 12b = 204
12a + 5b = 120
( - ) --------------
7b = 84
b = 12
Substitute b = 12 in eqn 1
4a + 4(12) = 68
4a + 48 = 68
4a = 20
a = 5
Thus cost of each senior ticket is $ 5 and cost of each child ticket is $ 12
