The magnitude of the electric field is [tex]1.51\cdot 10^{10}N/C[/tex]
Explanation:
The electrostatic force experienced by an electric charge immersed in an electric field is given by
[tex]F=qE[/tex]
where:
q is the charge of the particle
E is the strength of the electric field
F is the force
In this problem, we have:
[tex]q=+4.3\cdot 10^{-18}C[/tex] is the charge of the particle
[tex]F=6.5\cdot 10^{-8} N[/tex] is the force
Therefore, we can find the electric field by solving the equation for E:
[tex]E=\frac{F}{q}=\frac{6.5\cdot 10^{-8}}{4.3\cdot 10^{-18}}=1.51\cdot 10^{10}N/C[/tex]
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