Answer: [tex]tan(E)=1.70[/tex]
Step-by-step explanation:
For this exercise you need to remember the following Trigonometric Identity:
[tex]tan\alpha =\frac{opposite}{adjacent}[/tex]
You must observe the figure given in the exercise.
You can notice that the given triangle EFG is a Right triangle (Right triangles are defined as those triangles that have an angle that measures 90 degrees).
So, you can identify in the figure that:
[tex]\alpha=E\\\\ opposite=FG=56\\\\adjacent=EF=33[/tex]
So, knowing these values, you can substitute them into [tex]tan\alpha =\frac{opposite}{adjacent}[/tex] and then you must evaluate (Remember to round the result to the nearest hundreth).
Therefore, through this procedure you get:
[tex]tan(E)=\frac{56}{33}\\\\tan(E)=1.70[/tex]
