Brianna drove home from college traveling an average speed of 62.4 mph and drove back to the
college the following week at an average speed of 57.4 mph. If the total round trip took 9 hours,
how much time did it take Brianna to drive from home back to college? Express the time in hours
and minutes. Round to the nearest minute.

Respuesta :

Answer:   4 hours, 41 minutes

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Explanation:

point A = Brianna's college

point B = Brianna's home

d = distance from A to B

Going from A to B, she travels a distance d and has speed r = 62.4

d = r*t

d = 62.4*t

t = d/62.4

represents the time it takes to go from A to B.

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The time it takes to go from B to A is t = d/57.4 because her speed is now 57.4 mph

The total time is 9 hours, so,

(time going from A to B) + (time from B to A) = 9

(d/62.4) + (d/57.4) = 9

62.4*57.4 * ( d/62.4 + d/57.4 ) = 62.4*57.4 *9

57.4d + 62.4d = 32235.84

119.8d = 32235.84

d = 32235.84/119.8

d = 269.080467445742

d = 269.0805

The distance from Brianna's home to her college is approximately 269.0805 miles

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Time it takes going from B to A = d/57.4 = 269.0805/57.4 = 4.6878

It takes about 4.6878 hours to go from her home back to the college.

Convert from hours to hours+minutes

4.6878 hours = 4 hours + 0.6878 hours

4.6878 hours = 4 hours + (0.6878 hours)*(60 min/1 hr)

4.6878 hours = 4 hours + 41.268 minutes

4.6878 hours = 4 hours + 41 minutes ... rounding to the nearest minute

4.6878 hours = 4 hours, 41 minutes

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side note:

4 hrs, 41 min = 4*60 + 41 = 240+41 = 281 minutes