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PLEASE HELPPPPPP!!!!!!! A group of 40 trees in a forest are not growing properly. A botanist determines that 34 of the trees have a disease or are being damaged by insects, with 18 trees having a disease and 20 being damaged by insects. What is the probability that a randomly selected tree has both a disease and is being damaged by insects? Please explain so i can know how to do a similar question like this in the future

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ksceoo
It’s an 6 out of 40 percent probability or 27% chance out of 100%

The probability that a randomly selected tree has both a disease and is being damaged by insects is; 0.1

How to solve Conditional Probability?

We are told that group of 40 trees in a forest are not growing properly. Since 18 trees have a disease. Then;

Probability of having a disease is; P(A) = 18/40

Since 20 are damaged by insect, then probability of being damaged by insects is; P(B) = 20/40

34 of the trees have a disease or are being damaged by insects. Thus;

P(A or B) = 34/40

Thus;

P(A and B) = P(A) + P(B) - P(A or B)

P(A and B) = 18/40 + 20/40 - 34/40

P(A and B) = 4/40

P(A and B) = 1/10 = 0.1

Read more about Conditional Probability at; https://brainly.com/question/23382435

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