Margaret drove to a business appointment at 60 mph. Her average speed on the return trip was 50 mph. The return trip took one fifth
hr longer because of heavy traffic. How far did she travel to the​ appointment?

She traveled___miles.

Respuesta :

Margaret traveled 60 miles.

Step-by-step explanation:

Given,

Speed while driving to appointment = 60 mph

Let,

x be the time taken.

y be the total distance.

Distance = Speed * Time

y = 60x       Eqn 1

Speed while driving back = 50 mph

Time take = x+[tex]\frac{1}{5}\ hour[/tex]

Distance = Speed * Time

[tex]y=50(x+\frac{1}{5})\\\\y=50x+10\ \ \ Eqn\ 2[/tex]

As same distance is covered;

Eqn 1 = Eqn 2

[tex]60x=50x+10\\60x-50x=10\\10x=10[/tex]

Dividing both sides by 10

[tex]\frac{10x}{10}=\frac{10}{10}\\x=1[/tex]

Putting x=1 in Eqn 1

[tex]y=60(1)\\y=60\ miles[/tex]

Margaret traveled 60 miles.

Keywords: linear equation, subtraction

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