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Using the given equation find the missing coordinates of the points and then find the slope of the line for each equation
b) 3x−2y=12; A(...; 9), B(4; ...)

Respuesta :

Step-by-step explanation:

3x - 2y = 12

Substituting y = 9, we find:

[tex]3x - 2 \times 9 = 12 \\ \therefore \: 3x - 18 = 12 \\ \therefore \: 3x = 12 + 18 \\ \therefore \: 3x = 30 \\ \therefore \: x = \frac{30}{3} \\ \therefore \: x = 10 \\ \therefore \: A (...., 9) = A (10, \: 9) [/tex]

Similarly, solving for point B (4, __) =B (4, 0)

Coordinates of the the points A and B are (10, 9) and (4, 0) respectively and slope of the line will be [tex]\frac{3}{2}[/tex].

 Equation of a line given in the question → 3x - 2y = 12

Points A and B lying on the line are,

  • A(h, 9) and B(4, k)

Since, points A and B lie on the given line,

Satisfy the equation by the given points to find the unknown ordinates,

For A(h, 9),

3h - 2(9) = 12

3h = 12 + 18

h = [tex]\frac{30}{3}[/tex]

h = 10

For B(4, k),

3(4) - 2k = 12

2k = 12 - 12

k = 0

  Therefore, coordinates of points A and B will be (10, 9) and (4, 0) respectively.

Slope of the line passing through A and B will be,

Slope = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

          = [tex]\frac{9-0}{10-4}[/tex]

          = [tex]\frac{9}{6}[/tex]

          = [tex]\frac{3}{2}[/tex]

 Hence, points A and B are (10, 9) and (4, 0) respectively and slope of the line will be [tex]\frac{3}{2}[/tex].

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