a sample of bacteria taken from a river has an initial concentration of 2 million bacteria per milliliter and its concentration triples each week. a) find an exponential model that calculates the concentration after x weeks.b) estimate the concentration after 1.4 weeks.
A)B(x) =?
B) the estimated concentration of bacteria after 1.4 weeks is __ million per milliliter

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A. B(x)=2000000(3)^x

B.B(1.4)= 9311073 million per milliliter

Step-by-step explanation:

A.

The exponential formula to apply is;

[tex]y=Ab^t[/tex]

The starting amount =2000000, =A

The concentration triples each week, thus to find b, use x=1 and y=6000000 (concentration triple after each week)

Substitute in the formula as;

6000000=2000000*b¹

6=2*b¹

3=b¹

3=b

The exponential model is:

[tex]y=2000000(3)^t[/tex]

B(x)=2000000(3)^x

B.

The estimate concentration of bacteria after 1.4 weeks will be;

[tex]y=2000000*3^{1.4} \\\\\\y=2000000*4.66\\\\y=9311073[/tex]

B(1.4)= 9311073 million per milliliter

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Keywords : sample, bacteria, river, initial concentration, triples, week, exponential model,estimate

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The estimated concentration of bacteria after 1.4 weeks 5.488 million per milliliter

An exponential growth is given by:

y = abˣ

where y, x are variables, a is the initial value of y and b is the multiplier.

Let B(x) represent the concentration after x weeks.

a)

Since a river has an initial concentration of 2 million bacteria per milliliter and its concentration triples each week. Hence a = 2000000, b = 3, hence:

[tex]B(x)=2000000(3)^x[/tex]

b) the estimated concentration of bacteria after 1.4 weeks :

[tex]B(1.4)=2000000(1.4)^3=5488000[/tex]

The estimated concentration of bacteria after 1.4 weeks 5.488 million per milliliter

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