The right answer is Option A: pq(p+1)(p-1)
Step-by-step explanation:
Given expression is
[tex]p^3q-pq[/tex]
Taking pq common from the expression
[tex]pq(p^2-1)[/tex]
We know that;
[tex]a^2-b^2=(a+b)(a-b)[/tex]
Here;
[tex]a^2 = p^2\\b^2 = 1^2[/tex]
Therefore;
[tex]p^2-1=(p+1)(p-1)[/tex]
Thus, the expression becomes
[tex]pq(p+1)(p-1)[/tex]
The linear factors of [tex]p^3q-pq[/tex] are pq(p+1)(p-1)
The right answer is Option A: pq(p+1)(p-1)
Keywords: linear factors, common terms
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Answer: The right answer is Option A)
Step-by-step explanation: A I saw it on usatesprep
