Answer:
The values of x and y in the given equations are x=-5 and y=-8
Therefore the solution is (-5,-8)
Step-by-step explanation:
Given equations are [tex]8x-3y=-16\hfill (1)[/tex]
and [tex]5x+2y=-41\hfill (2)[/tex]
To solve the equations by elimination method :
Multiply the equation (1) into 2 we get
[tex]24x-6y=-32\hfill (3)[/tex]
Multiply the equation (2) into 2 we get
[tex]15x+6y=-123\hfill (4)[/tex]
Adding the equations (3) and (4) we get
16x-6y=-32
15x+6y=-123
___________
31x=-155
[tex]=\frac{-155}{31}[/tex]
Therefore x=-5
Substitute x=-5 in equation (1) we get
8(-5)-3y=-16
-40-3y=-16
-3y=-16+40
[tex]y=\frac{24}{-3}[/rex]
Therefore y=-8
The values of x and y in the given equations are x=-5 and y=-8
Therefore the solution is (-5,-8)
