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A block and tackle of six pulley is used to raise a load of 300N steadily through a height of 30m, if the workdone against friction is 2000j. Calculate;
1. The workdone by the effort
2. The efficiency of the system
3. The applied effort ​

Respuesta :

beingteenowfmao

Answer:

work accomplished = 300*30

= 9,000 J

applied work = 9,000 + 2,000 = 11,000 Joules

efficiency = 100 * work accomplished/work applied

= (9/11)100 = 81.8 %

force applied = (300/6)/.818

= 61.1 N

assuming that the 6 in your question refers to mechanical advantage

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