Jayden has $2.95 worth of dimes and quarters. He has 2 more quarters than dimes. Determine the number of dimes and the number of quarters that Jayden has.

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absor201 absor201 · Answer 1 · 2020-02-08T17:12:38+01:00

There are 7 dimes and 9 quarters Jayden has.

Step-by-step explanation:

Given,

Worth of dimes and quarters = $2.95 = 2.95*100 = 295 cents

One dime = 10 cents

One quarter = 25 cents

Let,

x be the number of dimes

y be the number of quarters

According to given statement;

10x+25y=295 Eqn 1

y = x+2 Eqn 2

Putting value of y from Eqn 2 in Eqn 1

[tex]10x+25(x+2)=295\\10x+25x+50=295\\35x=295-50\\35x=245[/tex]

Dividing both sides by 35

[tex]\frac{35x}{35}=\frac{245}{35}\\x=7[/tex]

Putting x=7 in Eqn 2

[tex]y=7+2\\y=9[/tex]

There are 7 dimes and 9 quarters Jayden has.

Keywords: linear equation, substitution method

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