Answer:
[tex]b=\frac{79}{3}[/tex] or [tex]b=26.33[/tex]
Step-by-step explanation:
Assuming the question to be finding the value of b.
[tex]3+\frac{1}{3}=b-23[/tex]
Solution:
Rewrite the equation as.
[tex]b-23=3+\frac{1}{3}[/tex]
first we solve right side of the equation.
[tex]b-23=\frac{3\times 3+ 1}{3}[/tex]
[tex]b-23=\frac{9+ 1}{3}[/tex]
[tex]b-23=\frac{10}{3}[/tex]
Add 23 both side of the equation.
[tex]b-23+23=\frac{10}{3}+23[/tex]
[tex]b=\frac{10+23\times 3}{3}[/tex]
[tex]b=\frac{10+69}{3}[/tex]
[tex]b=\frac{79}{3}[/tex]
or
[tex]b=26.33[/tex]
Therefore, the value of [tex]b=\frac{79}{3}[/tex] or [tex]b=26.33[/tex]
