Element X decays radioactively with a half-life of six minutes. If there are 310 g of element X, how long, to the nearest 10th of a minute, would it take the element to decay 2 grams

Respuesta :

The time taken is 43.7 min

Step-by-step explanation:

The equation that describes the amount of mass left after a time t of a radioactive isotope is the following:

[tex]m(t) = m_0 (\frac{1}{2})^{\frac{t}{\tau}}[/tex]

where

[tex]m_0[/tex] is the mass of the sample at t = 0

[tex]\tau[/tex]is the half-life of the sample

For the element X in this problem,

[tex]\tau = 6 min[/tex]

[tex]m_0 = 310 g[/tex]

We want to find the time t at which

[tex]m(t)=2g[/tex]

So we need to re-arrange the equation making t the subject:

[tex]\frac{m(t)}{m_0}=(2)^{-\frac{t}{\tau}}\\t=-\tau log_2(\frac{m(t)}{m_0})=-(6)log_2(\frac{2}{310})=43.7 min[/tex]

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