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In the United States, the generation of people born between 1946 and 1964 are known as baby boomers, and the generation of people born between 1981 and 1996 are known as millennials. Currently, 18 percent of the population are baby boomers and 27 percent of the population are millennials. A random sample of 500 people will be selected. Let the random variable B represent the number of baby boomers in the sample, and let the random variable M represent the number of millennials in the sample. By how much will the mean of M exceed the mean of B

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Answer:

45

Step-by-step explanation:

B = .18

M = .27

Sample size = 500

B(500) = 500(.18) = 90

M(500) = 500(.27) = 135

135 - 90 = 45

The mean of M will exceed the mean of B by 45 people when the sample size is 500.

francocanacari

The mean of millennials will exceed the mean of baby boomers by 45 people.

Since in the United States, the generation of people born between 1946 and 1964 are known as baby boomers, and the generation of people born between 1981 and 1996 are known as millennials and currently, 18 percent of the population are baby boomers and 27 percent of the population are millennials, and a random sample of 500 people will be selected, to determine by how much will the mean of millennials exceed the mean of baby boomers, the following calculation must be performed:

  • 500 x 0.27 - 500 x 0.18 = X
  • 135 - 90 = X
  • 45 = X

Therefore, the mean of millennials will exceed the mean of baby boomers by 45 people.

Learn more in https://brainly.com/question/1658528

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