If the copper is drawn into wire whose diameter is 9.50 mm, how many feet of copper can be obtained from the ingot? The density of copper is 8.94 g/cm3. (Assume that the wire is a cylinder whose volume is V=πr2h, where r is its radius and h is its height or length.)

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Answer:

The length of the wire = 352.66 feet.

Explanation:

A copper refinery produces a copper ingot weighing 150 lb. If the copper is drawn into wire whose diameter is 9.50 mm, how many feet of copper can be obtained from the ingot? The density of copper is 8.94 g/cm3. (Assume that the wire is a cylinder whose volume is V = πr2h, where r is the radius and h is its height or length.)

Step 1: Convert lb to kg

150 lb = 68.0389 kg

Step 2: Calculate volume of copper

Volume = mass / density

Volume = 68038.9 grams / 8.94 g/cm³

Volume = 7610.6 cm³ Cu

Step 3: Calculate length of wire

The diameter of the wire is 9.50 mm, so the radius is half of that (4.75 mm), or 0.475 cm.

The total "volume" of the wire is πr²h = (π)*(0.475 cm)²(h) = 0.708h = 7610 cm^3

7610 = 0.708h

h = 10749 cm = length of wire

The length of the wire = 352.66 feet.

The length of the wire is 2369.84cm

Data Given;

  • density = 8.94 g/cm^3
  • diameter = 9.50mm = 0.95cm
  • radius = d / 2 = 0.95/2 = 0.475cm
  • mass (not given, but assuming m = 15kg = 15000kg

Density of the Wire

Let's calculate the volume of the wire using formula of density.

[tex]density = \frac{mass}{volume}\\[/tex]

substitute the values and solve for volume

[tex]density = mass/ volume\\volume = mass / density \\volume = 15000/ 8.94\\volume = 1677.85cm^3[/tex]

Length of the Wire

To calculate the length of the wire, we would use the volume of a cylinder on this.

[tex]v = \pi r^2h\\1677.85 = 3.14 * 0.475^2 * h\\1677.85=0.708h\\h = 2369.84cm[/tex]

From the calculation above, the length of the copper is 2369.84cm

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