Answer:
The value of the given expression when z=27 is 16
Therefore [tex]\frac{7}{9}(z-18)+\frac{1}{3}z=16[/tex] when z=27
Step-by-step explanation:
Given expression is [tex]\frac{7}{9}(z-18)+\frac{1}{3}z[/tex]
To find the value of the expression when z=27 :
First simplify the given expression
[tex]\frac{7}{9}(z-18)+\frac{1}{3}z[/tex]
[tex]=\frac{7(z-18)}{9}+\frac{1}{3}z[/tex]
[tex]=\frac{7z-126}{9}+\frac{1}{3}z[/tex]
[tex]=\frac{7z-126+3z}{9}[/tex]
[tex]=\frac{7z-126+3z}{9}[/tex]
[tex]=\frac{10z-126}{9}[/tex]
Put z=27 in the above equation we get
[tex]=\frac{10(27)-126}{9}[/tex]
[tex]=\frac{270-126}{9}[/tex]
[tex]=\frac{144}{9}[/tex]
[tex]=\frac{144}{9}[/tex]
[tex]=16[/tex]
[tex]\frac{7}{9}(z-18)+\frac{1}{3}z=16[/tex]
Therefore the value of the given expression when z=27 is 16
Therefore [tex]\frac{7}{9}(z-18)+\frac{1}{3}z=16[/tex] when z=27
Answer:
Answer is 12
Step-by-step explanation:
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