Respuesta :
Answer:
The unknown substance is rhodium.
Explanation:
Heat lost by hot substance will be equal to heat gained by the water
[tex]-Q_1=Q_2[/tex]
Mass of substance= [tex]m_1=123.3 g[/tex]
Specific heat capacity of substance= [tex]c_1=?[/tex]
Initial temperature of the substance = [tex]T_1=164.2^oC[/tex]
Final temperature of substance= [tex]T_2=T=48.6^oC[/tex]
[tex]Q_1=m_1c_1\times (T-T_1)[/tex]
Mass of water = M
Volume of water ,V= 35 ml
Density of water = d = 1.00 g/mL
[tex]M=d\times V=1.00 g/ml\times 35 mL=35 g[/tex]
Mass of water= [tex]M = m_2=35 g[/tex]
Specific heat capacity of water= [tex]c_2=4.184 J/g^oC [/tex]
Initial temperature of the water = [tex]T_3=25.0^oC[/tex]
Final temperature of water = [tex]T_3=T=48.6^oC[/tex]
[tex]Q_2=m_2c_2\times (T-T_3)[/tex]
[tex]-Q_1=Q_2[/tex]
[tex]-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)[/tex]
On substituting all values:
we get, [tex]c_1 =0.242 J/g^oC [/tex]
The value of heat capacity of the substance is equal to that of rhodium metal.Hence, the unknown substance is rhodium.
