Answer:
Explanation:
Given
Power [tex]P=1.9\ J/s[/tex]
Also Power is given by
[tex]P=\frac{\rho \times A\times V^3}{2}----1[/tex]
Where P=Power delivered
[tex]\rho [/tex]=density of air
A=Area
V=Velocity of air
If we increase velocity by a factor of 2 Power changes to P'
[tex]P'=\frac{\rho \times A\times (2V)^3}{2}----2[/tex]
Divide 1 and 2
[tex]\frac{P}{P'}=\frac{V^3}{(2V)^3}[/tex]
[tex]P'=8 P[/tex]
[tex]P'=8\times 1.9=15.2\ J[/tex]
