Answer:
The buses will cross after 3 hours at a distance of 135 km away from Anandpur
Step-by-step explanation:
Distance between Anandpur and Shivnagar 255 km
Bus 1 leave at 1:00 p.m. Its speed is 45 km
Bus 2 leaves at the same time with a speed of 40 km/hour.
Now the Let the time at which ther across each other be x . then
Distance covered Bus 1 at t time +distance covered by Bus 2 at t time = distance between anandpur and shivnagar-----------------(1)
Distance covered Bus 1 at t time
Distance = speed x time
Distance = 45 t
Distance covered by Bus 2 at t time
Distance = speed x time
Distance = 40 t
Now, Substituting then values in (1)
45t +40t = 255
85t = 255
t =[tex]\frac{255}{85}[/tex]
t = 3 hour
anandpur speed to reach at 4:00PM
distance =time×speed
d=3×45
135 km away from anandpur
