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Judy (mass 45.0 kg), standing on slippery ice, catches her leaping dog, Atti (mass 10 kg), moving horizontally at 4.0 m/s. Use the conservation of momentum to find the speed of Judy and her dog after the catch. (m/s)

Respuesta :

Answer:

velocity of Judy and dog after collision will be 0.7272 m./sec

Explanation:

Mass of the Judy [tex]m_1=45kg[/tex]

As the Judy is standing so initial velocity of Judy [tex]v_1=0m/sec[/tex]

Mass of dog Atti [tex]m_2=10kg[/tex]

Velocity of Atti [tex]v_2=4m/sec[/tex]

We have to fond the velocity of Judy and dog after collision

Now according to conservation of momentum

Momentum before collision is equal to momentum after collision

So [tex]m_1v_1+m_2v_2=(m_1+m_2)v[/tex]

[tex]45\times 0+10\times 4=(45+10)\times v[/tex]

v = 0.7272 m/sec

So velocity of Judy and dog after collision will be 0.7272 m./sec

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