Respuesta :
The first equation must be multiplied by 18 and second equation must be multiplied by 8
Solution:
Given system of equations are:
[tex]\frac{1}{4}x -\frac{1}{6}y = 5[/tex] --------- eqn 1
[tex]\frac{4}{5}x +\frac{3}{8}y = 10[/tex] -------------- eqn 2
Multiply the second equation by 8 both sides to remove the fraction in the variable y
[tex]8(\frac{4}{5}x +\frac{3}{8}y = 10)\\\\\frac{32x}{5} + 3y = 80 -------- eqn 3[/tex]
Multiply the first equation by 18 both sides to obtain the coefficient -3 in the variable y
[tex]18(\frac{1}{4}x -\frac{1}{6}y = 5)\\\\\frac{18}{4}x -3y = 90 ---------- eqn 4[/tex]
Add eqn 3 and eqn 4
[tex]\frac{32}{5}x +3y +\frac{18}{4}x -3y = 80+90\\\\\frac{32}{5}x+\frac{18}{4}x = 170[/tex]
Thus the y-term is eliminated
Therefore, first equation must be multiplied by 18 and second equation must be multiplied by 8
Answer: A. 18 times the first equation and 8 times the second equation
Step-by-step explanation:
